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Maths Question (I call ALL the Geniuses)

This is a discussion on Maths Question (I call ALL the Geniuses) within the Technical Help forums, part of the Off Topic category; Ok i was doing some work and came across this: Find the Nth Term For : 5, 6, 8, 11, ...

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Old 05-05-08, 03:14 PM   #1
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Maths Question (I call ALL the Geniuses)


Ok i was doing some work and came across this:

Find the Nth Term For : 5, 6, 8, 11, 15

Anyone Know how to work this out?#

Thanks In Advance
 
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Old 05-05-08, 03:17 PM   #2
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Re: Maths Question (I call ALL the Geniuses)


20? lol

ah dinnae ken
 
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Old 05-05-08, 03:18 PM   #3
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Re: Maths Question (I call ALL the Geniuses)


Well I can see it's +1 +2 +3 +4 +5 +6 +7 etc if that helps...?
 
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Old 05-05-08, 03:20 PM   #4
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Re: Maths Question (I call ALL the Geniuses)


5+(n-1)!

where ! is factorial

i.e
1!=1
2!=1+2
3!=1+2+3

never mind; got it wrong - factorial is multiply; doh
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Old 05-05-08, 03:20 PM   #5
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Re: Maths Question (I call ALL the Geniuses)


i hate these too. i think sahou has the right idea, but how to put that into an answer...
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Old 05-05-08, 03:25 PM   #6
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Re: Maths Question (I call ALL the Geniuses)


think this might be GCSE stuff which is going back a bit but il have a go:

1st term of n = 5
2n = 8
3n = 11
4n=15

I could be wrong but i think the nth term is expressed by = n + (n-1) which is basically the term in the sequence plus the number in the sequence before it.

Eg 3rd term would be = 3 + (2nd term of 8) = 11 which is correct
 
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Old 05-05-08, 03:30 PM   #7
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Re: Maths Question (I call ALL the Geniuses)


5+ (n/2)*(n-1)
or
0.5*n^2 - 0.5*n + 5
 
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Old 05-05-08, 03:32 PM   #8
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Re: Maths Question (I call ALL the Geniuses)


Quote:
Originally Posted by andy5 View Post
5+ (n/2)*(n-1)
or
0.5*n^2 - 0.5*n + 5
yeah, that was the one - well done!
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Old 05-05-08, 03:35 PM   #9
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Re: Maths Question (I call ALL the Geniuses)


Quote:
Originally Posted by andy5 View Post
5+ (n/2)*(n-1)
or
0.5*n^2 - 0.5*n + 5
Thanks How did you work that out?
 
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Old 05-05-08, 03:54 PM   #10
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Re: Maths Question (I call ALL the Geniuses)


this isn't how i did it but i believe you can use this formulae

a + (n-1)d + 0.5(n-1)(n-2)C

Where a is the first term
d is the difference between the first term and second term
C is the difference increase

So in this case...
a=5
d= 1
for C 5 6 8 11 15
difference 1 2 3 4 so C=1
then you put the numbers into the equation and simplify

this may only work for changing difference formuales... cant really remember
 
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Old 05-05-08, 04:05 PM   #11
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Re: Maths Question (I call ALL the Geniuses)


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Old 05-05-08, 04:06 PM   #12
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Re: Maths Question (I call ALL the Geniuses)


Aye, what they said was right. However, if the difference is the same then you use this formula which is much easier.

nth term = dn + (a - d)
 
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Old 05-05-08, 04:07 PM   #13
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Re: Maths Question (I call ALL the Geniuses)


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Old 05-05-08, 04:12 PM   #14
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Re: Maths Question (I call ALL the Geniuses)


Quote:
Originally Posted by the_icks View Post
.
Why have you posted this? Twice? Also thanks for everyones help!!
 
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Old 05-05-08, 04:14 PM   #15
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Re: Maths Question (I call ALL the Geniuses)


Quote:
Originally Posted by Moneyboi View Post
Why have you posted this? Twice? Also thanks for everyones help!!
because you can only edit posts, you cant delete them. so, its the easiest way
 
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